28x^2+180x+72=0

Solution for 28x^2+180x+72=0 equation:

28x^2+180x+72=0

a = 28; b = 180; c = +72;
Δ = b2-4ac
Δ = 1802-4·28·72
Δ = 24336
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{24336}=156$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(180)-156}{2*28}=\frac{-336}{56}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(180)+156}{2*28}=\frac{-24}{56}
=-3/7
$